# Example case 1

### Step 1: calculate the reactions at the supports

The reactions at the supports of this simply supported beam can be determined by equilibrium calculations only, so the beam is statically determinate. The supports each provide a vertical reaction, but no horizontal or moment reaction. The equilibrium equations I will use are those for vertical equilibrium and moment equilibrium.

View video tutorial for step 1 (pop-up video)

### Step 2: form imaginary cut and draw free body diagram

In order to be able to calculate the shear force and bending moment at D, I introduce an imaginary cut in to the beam at D. This splits the actual beam in to two imaginary free bodies. I’ll choose to analyse the left hand section A to D, and draw it’s free body diagram.

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### Step 3: calculate force and moment at the imaginary cut

I will calculate the shear force and bending moment at D using my free body diagram and the equilibrium equations for vertical equilibrium and moment equilibrium. This is a similar process to what I did in step 1 to calculate the reactions at the supports.

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### Step 4: check calculation by analysing the second free body

In the check calculation, I choose to analyse the right hand section D to C. This must give me the same values I have already found for the shear force and bending moment at D, if I’ve already calculated these correctly.

View video tutorial for step 4 (pop-up video)